Question

Ans fast....................

Answer 1

Answer:

(3) 2 m/s

Explanation:

just find the loss of energy due to air resistance

at A

E= mgh...assume B on ground level

at B

E= 1/2mv^2

∆E = mgh-1/2mv^2= (mgh-10mgh/100).....10% of the total energy means energy initially

now h=2 as we assumed b at ground level

m(20-1/2v^2)= m(20-2)

20-1/2v^2 = 18

2= 1/2v^2

v^2=4

V=2 m/s

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