Ans fast please A deuteron and an a-particle are accelerated
through same potential difference. Then the
no
ratio of de-Broglie wavelengths
2
associated with them will be
Answers
Answered by
1
Answer:
From law of conservation of energy, Kinetic energy equals the change in electrical energy in the particle.
2
1
mv
2
=qV
p=mv=
2mqV
De-broglie wavelength of a particle is given by: λ=
p
h
λ=
2mqV
h
(a) Ratio of de-broglie wavelength of proton to deuteron is given by:
λ
d
λ
p
=
m
p
q
p
m
d
q
d
=
1×1
2×1
=
2
Hence, proton has a higher de-broglie wavelength.
(b) p=
λ
h
Hence, deuteron has higher momentum
if you like my answer pls support me
Similar questions