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stopping potential ,Vo is directly proportional to V .
therefore ,Vo2 / Vo1 = v2/v1
= 8× 10^15/4× 10^-5
= 2
since, Vo2 = 2Vo1
thus ,stopping potential will become double .
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1
Answer:
8*10^15/4*10^15
=2
therefore the stopping potential would increase by 2 times
thanks
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