Ans for question 12 plzzz!! And the formula too
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1)In triangle ABC ,angle A =60 and AB=AC
angle B=angle C _(isosceles triangle)
angleA+angleB+angleC=180 _ (triangle property)
60+a+a=180
60+2a=180
2a=180-60
2a=120
a=120÷2
a=60
BP is bisector of triangle ABC
angle ABC =angle ABP+ angle CBP
60=b+b
60=2b
60÷2 =b
b=30
In triangle ABP
angle A+angleB+angleP=180_(triangle property)
60+30+x =180
90+x=180
x=180-90
x=90
angle B=angle C _(isosceles triangle)
angleA+angleB+angleC=180 _ (triangle property)
60+a+a=180
60+2a=180
2a=180-60
2a=120
a=120÷2
a=60
BP is bisector of triangle ABC
angle ABC =angle ABP+ angle CBP
60=b+b
60=2b
60÷2 =b
b=30
In triangle ABP
angle A+angleB+angleP=180_(triangle property)
60+30+x =180
90+x=180
x=180-90
x=90
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