Question

Ans for the vikram question
Wat are the rod lengths

Answer 1

Hey mate!

Here's your answer!!

Let 'h', 'b' and 'a' be the hypotenuse, base and altitude of the triangle respectively.

So, according to the question,

h = 2 + b (i)

h = 4 + a (ii)

From 1 and 2,

2+b = 4+a

=> b = 2+a (iii)

Now, according to pythagoras theorem,

h² = a² + b²

From (ii) and (iii),

(4+a)² = a² + (2+a)²

=> 16 + 8a + a² = a² + 4 + 4a + a²

Rearranging,

=> a² - 4a - 12 = 0

=> a² - 6a + 2a - 12 = 0

=> a (a-6) + 2(a-6) = 0

=> (a-6) (a+2) = 0

=> a = 6 or -2

Since altitude of a triangle cannot be in -ve,

Altitude = 6cm

Putting value of a in (iii),

Base = 2 + 6 = 8cm

Also, putting value of b in (i),

Hypotenuse = 2 + 8 = 10cm

Therefore,

Base = 8 cm

Altitude = 6 cm

Hypotenuse = 10 cm.

$hope \: it \: helps \: you....$
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