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Weight of Sodium Chloride given = 5.85 g
Molecularmass = Na + Cl = 23 + 35.5 = 58.5 u
Now no of moles = Weight of compound / Molecular mass
No of moles = 5.85 / 58.5 = 0.1 gmu
Now we know that there are 6.022 * 10^23 atoms particles molecules ions etc in 1 mole of an element or compound by Avogadro number rule
Thusthere 6.022 * 10^23 / 10 ions = 6.022 * 10^22 ions in 5.85 g of Sodium Chloride.
Molecularmass = Na + Cl = 23 + 35.5 = 58.5 u
Now no of moles = Weight of compound / Molecular mass
No of moles = 5.85 / 58.5 = 0.1 gmu
Now we know that there are 6.022 * 10^23 atoms particles molecules ions etc in 1 mole of an element or compound by Avogadro number rule
Thusthere 6.022 * 10^23 / 10 ions = 6.022 * 10^22 ions in 5.85 g of Sodium Chloride.
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