Question

ans fst plz








jshshsnsgsjrbusnrjfxd​

Answer 1

${ (\frac{2}{9}) }^{3} \times {( \frac{2}{9} )}^{ - 6} = {( \frac{2}{9} )}^{2m - 1}$

We see here that the bases are same in the LHS and RHS. Therefore, we can neglect the bases and count on the exponents.

$3 - 6 = 2m - 1$

$- 3 = 2m - 1$

$- 3 + 1 = 2m$

$2m = - 2$

$m = - 1$