Math, asked by parvrajjain27p7hszu, 11 months ago

ans it fast iit jee mains que​

Attachments:

Answers

Answered by waqarsd
2

if \:  \alpha \: and \:   \beta  \: are \: the \: roots \: of \: equation \\  \\ a {x}^{2}  + bx + c = 0 \\  \\  \alpha   + \beta  =  -  \frac{b}{a}  \\  \\  \alpha  \beta  =  \frac{c}{a} \\  \\ now \: given \\  \\ 2 {x}^{2}  + 3x + 4 = 0 \\  \\  \alpha  +  \beta  =  -  \frac{3}{2}  \\  \\  \alpha  \beta  = 2 \\  \\  { \alpha }^{2}  +  { \beta }^{2}  \\  \\  =  { \alpha }^{2}  +  { \beta }^{2}  + 2 \alpha  \beta  - 2 \alpha  \beta  \\  \\  {( \alpha   + \beta )}^{2}  - 2 \alpha  \beta  \\  \\  =  \frac{9}{4}  - 4 \\  \\  =   -  \frac{7}{4}  \\  \\  \frac{ \alpha }{ \beta }  +  \frac{ \beta }{ \alpha }  \\  \\  =  \frac{ { \alpha }^{2}  +  { \beta }^{2} }{ \alpha  \beta }  \\  \\  =  \frac{( -  \frac{7}{4} )}{2}  \\  \\  =  -  \frac{7}{8}

hope it helps.

Similar questions