Question

ans it for 50 points spam will be reported​

Answer 1

Answer:

Factoring t2-2t-9

The first term is, t2 its coefficient is 1 .

The middle term is, -2t its coefficient is -2 .

The last term, "the constant", is -9

Step-1 : Multiply the coefficient of the first term by the constant 1 • -9 = -9

Step-2 : Find two factors of -9 whose sum equals the coefficient of the middle term, which is -2 .

9 + 1 = -8

-3 + 3 = 0

-1 + 9 = 8

is it ok ????

Answer 2

★FIND:

The value of 't'

★GIVEN:

$\bold{t^2-2t+9=0}$

★SOLUTION:

$\bold{t^2-2t+9=0}$

$\bold{where,}$

$\bold{a=1}$ ,$\bold{b=-2,}$ $\bold{c=9}$

$t = \frac{ - b + - \sqrt{b {}^{2} - 4ac } }{2a}$

$= \frac{ - ( - 2) + - \sqrt{4 - 4(1)(9)} }{2(1)} \\ = \frac{2 + - \sqrt{4 - 36} }{2} \\ = \frac{2 + - \sqrt{32} }{2} \\ = \frac{2 + - \sqrt{16 \times 2} }{2} \\ = \frac{2 + - 4 \sqrt{2} }{2} \\ =1 + - 2 \sqrt{2} \\ t = 1 + 2 \sqrt{2} \: or \: t = 1 - 2 \sqrt{2}$