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let the first no be x so the next one will be
x+1 and the third one will be
x+1+1
sn = n/2 { 2a +(n-1) d}
here a = x , n= 5 , d = 1 , total sum (sn) = 135
135 = 5/2 { 2x + (5-1) 1}
135× 2/5 = 2x + 4
27 × 2 = 2x+ 4
54 = 2x+ 4
2x = 54-4
2x= 50
x= 50/2
x= 25
so the first no is 25 second 25+1 = 26 third 27 fourth 28 fifth = 29
= 25,26,27,28,29
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