Math, asked by rutushivashankar, 11 months ago

ans it plzzzzz.because I want it now ​

Attachments:

Answers

Answered by vibhapande5674
1

Hey Mate,

Your answer is in the attachment, kindly check it from there

MARK AS BRAINLIST

Attachments:
Answered by mehtadaksh2965
4

Answer:

\huge \ \fcolorbox{aqua}{aqua}{hi \: bro}

Step-by-step explanation:

 \ \fcolorbox{aqua}{aqua}{your \: answer \: is : }

{ \red{let \: the \: speed \: of \: boat \: be \: xkmh}}

{ \red{speed \: of \: water \: be \: ykmh}}

{ \green{by \: given \: condition}} \\  \frac{30}{x - y}  +  \frac{44}{x + y}  = 10 \\  \frac{40}{x - y}  +  \frac{55}{x - y}  = 13

{ \orange{let \:  \frac{1}{x - y} \: be \: u \: and \:  \frac{1}{x + y}be \: v  }}

30u + 44v = 10 \:  \:  \: eq \: 1 \\ 40u + 55v = 13  \:  \:  \: eq \: 2

using \: cross \: multiplication \\  \: { \red{(u \: can \: use \: any \: method)}}

 \frac{u}{(44)( - 13) - (55)( - 10)}  =  \frac{v}{ (- 10)(40) - ( - 13)(30)}  =  \frac{1}{(30)(55) - (40)(44)}

therefore \:  \frac{u}{ - 22}  =  \frac{v}{ - 10}  =  \frac{1}{ - 110}

u =  \frac{1}{5}  \: v =  \frac{1}{11}

therefore \: x + y = 11 \: eq \: 3 \\ x - y = 5 \: eq \:  \: 4

2x = 16 \\ x = 8

2 y = 6 \\ y = 3

{ \red{this \: is \: by \: adding \: eq3 \: and \: 4}}

 \ \fcolorbox{aqua}{aqua}{hence \: speed \: of \: boat is \: 8kmh \: speed \: of \: water \: is \: 3 \: kmh}

\huge \ \fcolorbox{aqua}{aqua}{follow \: me}

Similar questions