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Answered by
1
vi) Well take 2^n common, we get
= 2^n (1 + 2^-1) / 2^n(2^1 - 1)
2^n will cancel each other
= ( 1 +1/2 ) / (2 - 1)
= (3/2) / 1
= 3/2 = RHS
Hence proved
= 2^n (1 + 2^-1) / 2^n(2^1 - 1)
2^n will cancel each other
= ( 1 +1/2 ) / (2 - 1)
= (3/2) / 1
= 3/2 = RHS
Hence proved
Answered by
3
hope it will help you..
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