Question

Ans me pls it's urgent ​

Answer 1

(x^2-y^2)+(y^2-z^2)+(z^2-x^2)

=x^2-y^2+y^2-z^2+z^2-x^2

=0

Answer 2

Solution:

Given Expression:

= (x - y)(x + y) + (y - z)(y + z) + (z - x)(z + x)

We know that:

→ (a + b)(a - b) = a² - b²

Applying the above identity, we get:

= (x)² - (y)² + (y)² - (z)² + (z)² - (x)²

= (x² - x²) + (y² - y²) + (z² - z²)

= 0

Therefore:

→ (x - y)(x + y) + (y - z)(y + z) + (z - x)(z + x) = 0

★ Which is our required answer.

Answer:

• (x - y)(x + y) + (y - z)(y + z) + (z - x)(z + x) = 0

Learn More:

Algebraic Identities.

• (a + b)² = a² + 2ab + b²
• (a - b)² = a² - 2ab + b²
• a² - b² = (a + b)(a - b)
• (a + b)³ = a³ + 3ab(a + b) + b³
• (a - b)³ = a³ - 3ab(a - b) - b³
• a³ + b³ = (a + b)(a² - ab + b²)
• a³ - b³ = (a - b)(a² + ab + b²)
• (x + a)(x + b) = x² + (a + b)x + ab
• (x + a)(x - b) = x² + (a - b)x - ab
• (x - a)(x + b) = x² - (a - b)x - ab
• (x - a)(x - b) = x² - (a + b)x + ab
• (a + b + c)² = a² + b² + c² + 2(ab + bc + ac)