ans of 3rd question plzz
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sanjaycharanr:
its 60
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in triangle BCD
ANGLE DBC + ANGLE DCB + ANGLE BDC = 180
ANGLE BDC = 180 - 60 = 120
ANGLE BDC + ANGLE BAC =180 ( CYCLIC QUADRILATERAL )
ANGLE BAC = 60° ANSWER.
ANGLE DBC + ANGLE DCB + ANGLE BDC = 180
ANGLE BDC = 180 - 60 = 120
ANGLE BDC + ANGLE BAC =180 ( CYCLIC QUADRILATERAL )
ANGLE BAC = 60° ANSWER.
how 180-60?
how 60 came?
triangle Bdc is isosceles so base angles are 30 each
ooh ya
thank you soo much
your welcome.
glad to help you
Answered by
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60° is the measure of angle BAC.
Remember angle ABC is 90° (angle formed in a semi-circle)
Remember angle ABC is 90° (angle formed in a semi-circle)
So how 60?
plzz explain
Given that:
??
plzz tellll
BD=DC , <DBC=30° and O is center of circle. <BAC=120° angle subtend by semi circle.
ABCD is a cyclic quad
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