ans of 6th question plzz
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We will draw the diagnol BD of the quadrilateral.
We know that the sum of two angles of a triangle is equal to the exterior angle of the third side.
Here, in triangle CBD,
Angle CBD+ Angle CDB= a
In triangle ABD,
Angle ABD+ Angle ADB= b
Adding both, we get
Angle CBD+ Angle ABD+ Angle CDB+ Angle ADB= a+b
But Angle CBD+ Angle ABD= x and Angle CDB+ Angle ADB= y
Therefore,
x+y= a+b
Hope it helps! Please mark it as 'Brainliest'!
We know that the sum of two angles of a triangle is equal to the exterior angle of the third side.
Here, in triangle CBD,
Angle CBD+ Angle CDB= a
In triangle ABD,
Angle ABD+ Angle ADB= b
Adding both, we get
Angle CBD+ Angle ABD+ Angle CDB+ Angle ADB= a+b
But Angle CBD+ Angle ABD= x and Angle CDB+ Angle ADB= y
Therefore,
x+y= a+b
Hope it helps! Please mark it as 'Brainliest'!
sandy72:
Thank you ji
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