Question

Ans of this Question

Answer 1

Answer:

32 would be the answer.

Answer 2

$Let \: watch = x , calculator = y \: and \\bulb = z$

/* According to the problem given */

$i )3x = 21$

$\implies x = \frac{21}{3} = 7\: --(1)$

$ii ) 3y = 30$

$\implies y = \frac{30}{3}$

$\implies y = 10 \: --(2)$

$iii) z = 15 \: --(3)$

$\red{ x + y \times 3z } \\= 7 + 10 \times 45\\= 7 + 450 \\= 457$

Therefore.,

$\red{ watch + calculator \times 3(bulbs) } \green { = 457 }$

•••♪