Question

ans only if u know......
make sure your ans is :-
angle PCD = 44 degrees
angle CPD = 80 degrees​

Answer 1

Answer:

Hii your solution ✌✌

I hope it's helping for you ✌✌

Answer 2

Answer:

$\huge{\pink{\boxed{\green{\sf{\therefore \angle PCD=44\degree}}}}}$

$\huge{\pink{\boxed{\green{\sf{\therefore \angle CPD=80\degree}}}}}$

Step-by-step explanation:

$\huge{\pink{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}$

$\: \: \: { \orange{given}} \\ { \pink{ \boxed{ \green{ \angle \: BAD = 56 \degree}}}} \\ { \pink{ \boxed{ \green{ \angle \: APC = 100 \degree}}}} \\ \\{ \blue {to \: find}} \\ { \purple{ \boxed{ \red{ \angle \:PCD =?}}}} \\ { \purple{ \boxed{ \red{ \angle \:CPD =? }}}}$

☆ According to given question :

☆ AB//CD [GIVEN]

$\to \angle BAD = \angle PDC \: \: (alternate \: angle) \\ \to \angle PDC = 56 \degree \\ \\ \to \angle APC = \angle PDC + \angle PCD \: \: \: (exterior \: angle = sum \: of \: interior \: opposite \: angle) \\ \to 100 \degree= 56 \degree + \angle PCD \\ \to \angle PCD= 100 \degree - 56 \degree \\ { \pink{ \boxed{ \green{\to \angle PCD = 44 \degree}}}} \\ \\ \to \angle APC + \angle CPD = 180 \degree \: \: \: \: (linear \: pair) \\ \to 100 \degree + \angle CPD = 180 \degree \\ \to \angle CPD = 180 \degree - 100 \degree \\{ \pink{ \boxed{ \green{ \to \angle CPD = 80 \degree}}}}$

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