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Answer:
Const. - Draw a line PQ through E such that AB || PQ || CD
Now ,
Since , AB || PQ (By Const.)
So,. AB || PE and BE is transversal.
angle(ABE + PEB) = 180° (Corresponding ang.)
120° + angle PEB= 180°
AnglePEB = 180° - 120° = 60°
Again ,
CD || PQ ( by const. )
So, CD || EQ and CE is transversal .
Angle (DCE + QEC ) = 180° ( corresponding Angle )
100° + angle QEC = 180°
angle QEC = 180° - 100° = 80°
Now,
Angle(PEB + BEC + QEC ) = 180° ( Straight line property )
60° + x + 80° = 180°
x = 180° - 140° = 40° Ans...
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