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Answer:
Given:
A binary system has been provided consisting of 2 masses.
The initial force of attraction is F = x
Now, the distance has been doubled.
To find:
New force of attraction
Calculation:
Initially:
F = G(M1)(M2)/d² = x ........(1)
Final case:
F" = G(M1)(M2)/(2d)²
=> F" = G(M1)(M2)/4d²
=> F" = ¼[G(M1)(M2)/d²]
=> F" = ¼[F]
=> F" = ¼x
So the final answer is F" = ¼x.
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Hey!
Good question
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