Math, asked by Anonymous, 4 months ago

ans pls..........
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Answered by Anonymous
3

☆ANSWER☆

1. (i) SOLUTION

103×97=(100+3)(100−3)

Using, a2−b2=(a+b)(a−b)

=(100)2−(3)2

=10000−9

=9991

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(ii) SOLUTION

105×105 is similar to 105^2

(105)^2=(100+5)2        [(a+b)^2=a^2+b^2−2ab]

=(100)^2+(5)^2+2(5)(100)

=10000+25+1000

=11025.

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14. SOLUTION

∠ACB=50°,∠ACB=∠CAD(∵BC∣∣AD)

In △AOD,∠DAO+∠ADO+∠AOD=180°

50+∠ADB+90°=180°

∠ADB=180°−140°=40

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HAVE A GREAT DAY AHEAD ❣

Answered by monishsahil2008
4

Answer:

9991

Step-by-step explanation:

(1). 103×97=(100+3)(100-3)

using a2-b2=(a+b)(a-b)

=(100)2-(3)2

=10000-9

99991

hope you will understand my answer

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