Ans pls the question please
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Step-by-step explanation:
(x^a-b)^a+b × (x^b-c)^b+c × (x^c-a)^c+a
= x^(a^2 - b^2) × x^(b^2- c^2) × x^(c^2-a^2)
= x^(a^2-b^2+b^2-c^2+c^2-a^2)
=x^0
=1
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