Question

Ans pls the question please

Answer 1

Step-by-step explanation:

(x^a-b)^a+b × (x^b-c)^b+c × (x^c-a)^c+a

= x^(a^2 - b^2) × x^(b^2- c^2) × x^(c^2-a^2)

= x^(a^2-b^2+b^2-c^2+c^2-a^2)

=x^0

=1