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Given:
- Volume of gas occupied at 0°C = 3L
- Temperature of gas 1 = 0°C
- Pressure is constant
To find:
- Volume of same gas at -20°C
Solution:
Using Charles law
V1/T1 = V2/T1
Where
V1 : Volume of gas 1 = 3L
T1 : temperature of gas 1 = 0°C = 273K
V2 : volume of gas 2 = ?
T2 : Temperature of gas 2 = -20°C = 253K
Substituting the values we have
→ 3/273 = V2/253
→ 3(253)/273 = V2
→ 759/273 = V2
→ V2 = 2.78 L
Hence ,volume becomes 2.78 L
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