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integral(x+2x2+3)dx
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Answer:
Let u=2−x , then du=−dx
∫3(2−x)2dx=−∫3u2du=−3⋅u−2+1−2+1+C=3u+C=32−x+C
Step-by-step explanation:
Answered by
0
Answer:
The definite integral of
2
x
2
+
3
on the interval
[
4
,
6
]
can be expressed as:
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