Question

ans que no. 10
Plz ans it fast and ans only if u know how to do it.

Answer 1

1) Given : in ΔABC ,
D,E are mid points of AB and AC

RTP : arΔADE = arΔABC/4

proof :in ΔABC and ΔADE

<A = <A [common angle]
AB/AD = AC/AE =2/1 [ D is the mid point of AB ]
therefore
ΔABC similar to ΔADE

ar(ADE)/ar(ABC) = (AD)²/(AB)²
{since if two triangle are similar ratio of their areas equal to ratio of their corresponding sides}
ar ΔADE= 1²/2² * ar ΔABC

= 1/4 *ΔABC