Question

ans question 1 and 2 and 3,4

Answer 1

Hope this will help u

Answer 2

$\large{\bold{\boxed{Hoi!}}}$

$\bold{\underline{Solution}}$

i).
{(x-1)/2} - x = {(x-2)/3} -1

=> (x - 1 - 2x)/2 = (x - 2 - 3)/3

=> (-x -1)/2 = (x-5)/3

by cross-multiplicitation we get,

3(-x - 1) = 2(x-5) => -3x -3 = 2x - 10

=> 2x + 3x = 10 - 3
=> 5x = 7
=> x= 7/5

$\textbf{Similarly, solve Q. 2!}$

iii).

(x-3)(x-2) ÷ (2x+1)(x-4) = 1/2

=> (x²+6-3x-2x) ÷ (2x²-8x+x-4) = 1/2

=> 2(x²+6-5x) = 2x²-7x-4

=> 2x²-10x+12 = 2x²-7x-4

=> 10x-7x = 12+4 (elemination of 2x² from both sides)

=> 3x = 16

=> x = 16/3

$\textbf{Similarly solve Q4.}$

And let me know if there's still something to explain!...

$\bold{\underline{Thanks!}}$☺️