Question

ans step by step please,​

Answer 1

Answer:

e). Let us assume, the present age of Seema is x years and the present age of Beena is y years.

Given:

x = y + 9

x - y = 9 ------------1

Also given:

x + 10 = 2 (y - 10)

x + 10 = 2y - 20

2y -x = 30 ------------2

Adding equation 1 and equation 2

y = 39 years

Therefore, x = y + 9 = 39 + 9 = 48 years

Answer - The present age of Seema is 48 years and the present age of Beena is 39 years.

f). Let age of two sisters be x and y,

x−y=10 (1)

x−15=20 (2)

x−15=2(y−15) (3)

Substituting (2) in (3)

20=2y−30

50=2y

y=25 (4)

Substituting (4) in (1)

x−25=10

x=35

Their present ages are 35 years and 25 years.

hope it helps you

Answer 2

Answer:

Seema is 48 years old.

Beena is 39 years old.

Step-by-step explanation:

Suppose that Beena's age is x, then Seema's would be x+9. Using this knowledge, we can proceed with the equation of Seema's age 10 years from now.

$x + 9 + 10 \: years = 2(x - 10 \: years)$

this is the equation for their ages from the second part of the question.

Therefore,

$x + 19 = 2x - 20 \\ 20 + 19 = 2x - x \\ x = 39$

And since we have let Beena's age be x, proceed to substitution for Seema's age, x+9=48.