Question

ans the above question
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Answer 1

Step-by-step explanation:

herehere first we will assume the given zeros to be a and b then we will find the sum and product of the zeros and the subject to the respective values to get the desired quadratic equation the quadratic polynomial is into 2 minus 2 into minus 3

Answer 2

from given 3+√2 and 3-√2 are roots of a quadratic polynomial

hence

{x-(3+√2)}{x-(3-√2)}=0

(x-3-√2)(x-3+√2)=0

x^2-3x+√2x-3x+9-3√2-√2x+3√2-2=0

x^2-6x+7=0