Ans the following ...........
1) 3 consecutive terms in G.P
2) 4 consecutive terms in G.P
3) 5 consecutive terms in G.P
4) 6 consecutive terms in G.P
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Step-by-step explanation:
Let the first term of G.P be
.
⇒ second term = a and third term = ar.
(where, r is the common ratio)
∵ sum of three terms is 156
⇒ a3 = 216
⇒ a = 6. ……..(1)
Also,sum of their product in pairs is 216.
………(2)
Substituting (1) in (2), we get-
⇒ 36(1 + r + r2) = 156r
⇒ 36 + 36r + 36r2 = 156r
⇒ 36 -120r + 36r2 = 0
⇒ 12(3r2-10r + 3) = 0
⇒ 3r2-10r + 3 = 0
⇒ 3r2-9r-1r + 3 = 0
⇒ 3r(r-3) -1(r-3) = 0
⇒ (3r-1)(r-3) = 0
Now, G.P will be-
⇒18, 6, 2 or 2, 6, 18 are the three consecutive terms
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