Math, asked by ritwika2007, 11 months ago

Ans the following


Q1. A rhombus-shaped field has green grass for 18 cows to graze. If each side of the rhombus is 30 m and its longer diagonal is 48 m, how much area of grass field will each cow be getting?


Q2. Find the cost of laying grass in a triangular field of sides 50 m, 65 m and 65 m at the rate of Rs 7 per m2.


Q3. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3: 2. Find the area of the triangle.


Q4. How much paper of each shade is needed to make a kite given in the figure, in which ABCD is a square with diagonal 44 cm.


Q5. A rectangular plot is given for constructing a house, having a measurement of 40 m long and 15 m in the front. According to the laws, a minimum of 3 m, wide space should be left in the front and back each and 2 m wide space on each of other sides. Find the largest area where a house can be constructed.

Answers

Answered by skchoudary
1

Answer:

  1. side = 30 m

    diagonal = 48 m

so , other diagonal = √30*2 - 24*2

                                 = √900 - 576

                                  = √324 = 18 m

so , area = 1/2 * 48*36

               = 864 m units

For 18 cows = 864 / 18

                     = 48 m units

Step-by-step explanation:

Similar questions