ans the q
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u don't know ans don't write.
(fake ans)
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Answer:
ABPD is a cyclic quad.
-angle DPC is equal to angle DAB (exterior angle of a cyclic quad is equal to the interior opposite angle).
-anlge C is equal to angle DAB.(angles of a parallelogram )
Therefore angle DPC is equal to angle C(all equal to angle DAB).
Therefore triangle DPC is an isosceles triangle.
And DC=DP (opposite sides of isosceles triangle are equal)
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I think mark as brainlist please
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