Question

ans the question plzzz questions no.30 and 31​

Answer 1

Answer:

Answer 31

The expansion of x²-1 is x+1and x-1

Then first put the value of the first factor in the polynomial which is -1

in which the answer is a-b+c-d+e then rearrange the terms we get

a+c+e=b+d

Then put the value of the second factor in the polynomial which is +1

Then you'll get the answer as follows

a+b+c+d+e=0

(a+c+e) + (b+d) = 0

Then in place of b+d put a+c+e because it is equal to it then you'll obtain this

(a+c+e.) + (a+c+e )= 0

2(a+c+e)= 0

(a+c+e)= 0/2

therefore b+d = a+c+e = 0

Answer 2

hope it helps you gys
at last a lot of thanks