Question

Ans the question
quadratic equations​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

x = (23 ± √493)/2

Step-by-step explanation:

$\frac{x}{5} + \frac{28}{x+2} = 5$

$\frac{x(x+2)+140}{5(x+2)} = 5\\\\\frac{x^{2} + 2x + 140}{5x+10} = 5\\\\x^{2} + 2x + 140= 5(5x+10)\\\\x^{2} + 2x + 140= 25x + 50\\\\x^{2} - 25x+2x +140-50=0\\\\x^{2} - 23x + 9 = 0$

Using Quadratic equation:

x= {-b ± √(b²-4ac)}/2a = (23 ± √529-36)/2 = (23 ± √493)/2

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