Question

ans the question tick mark one​

Answer 1

it is your answer to your question

Answer 2

Steps:

1)Radius of circle, r =7√2 cm

Since,

/ABC = /ACB = 45° (Angles opposite. to equal sides are equal)

By Angle sum property of triangle,

/ABC = 180° -45° -45° = 90°

Angle of sector,theta = 90°

2) We know,

Area of segment ,

\begin{lgathered}= \frac{ {r}^{2} }{2} ( \frac{\pi \theta}{180 \degree} - \sin( \theta) ) \\ = > \frac{( {7 \sqrt{2} )}^{2} }{2} ( \frac{\pi \times 90\degree}{180 \degree} - \sin( 90 \degree) ) \\ = > 49( \frac{\pi}{2} - 1) \: {cm}^{2}\end{lgathered} = 2r 2

( 180°πθ−sin(θ))=> 2(7 2 ) 2

( 180°π×90° −sin(90°))

=>49( 2π−1)cm

2

Hence, Area of segment is

\boxed { 49( \frac{\pi}{2} - 1) {cm}^{2} }

49( 2π−1)cm

2