Question

ans the questions in image​

Answer 1

Step-by-step explanation:

Q60. tan²A-sin²A

=(sin²A/cos²A)-sin²A

=sin²A-sin²Acos²A/cos²A

=sin²A(1-cos²A)/cos²A

=sin²A.sin²A/cos²A

=tan²A.sin²A

Q61.(secA+cosA)(secA-cosA)

=sec²A-cos²A

=1+tan²A-1+sin²A

=tan²A+sin²A

Q62.(secA+tanA-1)(secA-tanA+1)

={secA+(tanA-1)}{secA-(tanA-1)}

=(secA)²-(tanA-1)²

=sec²A-(tan²A-2tanA+1)

=sec²A-tan²A+2tanA-1

=1+2tanA-1

=2tanA

=2/cotA