Question

ans these questions....

Answer 1

I)
$\text{ FeO = Iron(II) oxide}$
It is also called ferrous oxide. It is a simple oxide. Here, oxidation state of iron is 2.

$\text{Fe_2O_3}\ :\ \text{Iron(III) oxide}$
It is also called ferric oxide. It is a simple oxide. Here, oxidation state of iron is 3.

$\text{Fe_3O_4}\ :\ \text{Iron(II,III) oxide}$
It is also called ferrous ferric oxide. It is a compound oxide as iron is present in two oxidation states. Here, oxidation state of iron is 2 and 3.
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ii)
$\text{Fe + H_2O}$ gives a number of products depending on the condition. See which equations are given in your book.

Most probably, it will form:
$\text{Fe + H_2O} =$ $\text{FeO + H_2}$

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iii)
The chemical equation for the formation of rust is:

$\text{Iron + Water + Oxygen = Rust}\\ \\ \text{4Fe(s) + 6H_2O(l) + 3O_2(g)}=$ $\text{4Fe(OH)_3}$

Then Fe(OH)3 dehydrates to produce $\text{Fe_2O_3.nH_2O}$ which is the formula of rust.

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IV)
$\text{MnO_2\ + \ 4HCl\ = \ MnCl_2\ + \ 2H_2O\ + \ Cl_2}$

It is a Redox reaction.

Here, MnO2 is losing oxygen. So MnO2 is being reduced. More specifically, Mn is being reduced.

Other reactant will be oxidised. So HCl is oxidised(You can say it is losing Hydrogen, so it is oxidised). More specifically, it is Cl which is being oxidised.