Question

ans theses question​

Answer 1

Answer:

• Resistance of the ammeter is RA (480 $2)(20 92) = = 19.2Q (480 £2 + 20 52) (As 480 22 and 20 Q are in parallel)
• As ammeter is in series with 40.8 22, Total resistance of the circuit is R = 40.8 Q2 + R₂ = 40.8 Ω + 19.2 Ω = 60 Ω By Ohm's law,
• Current in the circuit is V 30 V 1 =-= R 60 Ω 1 2 = A = 0.5 A Thus the reading in the ammeter will be 0.5A

Answer 2

Answer:

Resistance of the ammeter is RA (480 $2)(20 92) == 19.2Q (480 £2 + 20 52) (As 480 22 and 20 Q are in parallel)

• As ammeter is in series with 40.8 22, Total resistance of the circuit is R = 40.8 Q2 + R₂ = 40.8 +19.2 = 60 Q By Ohm's law,

• Current in the circuit is V 30 V 1 =-= R 60 0212= A=0.5 A Thus the reading in the ammeter will be 0.5A