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(1) , x is inversly proportional to √y.
Given, x = 40 then y = 16
if x = 10 then , y = ???
40 × √16 = 10 × √y
=> √y = 40×4/10
=> y = 16^2
=> y= 256
(2) x1 = 15 y1 = 10
x = 20 y= ???
15×10 = 20×y
=> y = 15×10/20
=> y = 15/2
(1) , x is inversly proportional to √y.
Given, x = 40 then y = 16
if x = 10 then , y = ???
40 × √16 = 10 × √y
=> √y = 40×4/10
=> y = 16^2
=> y= 256
(2) x1 = 15 y1 = 10
x = 20 y= ???
15×10 = 20×y
=> y = 15×10/20
=> y = 15/2
misses72:
sry but 1 ka ans 256 hy surf method janna tha
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