Math, asked by samikshaa28, 4 months ago

ans this maths question.
clearly n urgent ​

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Answered by xXBangtanGirlXx
4

Let the speed of the boat in still water be x km/hr and the speed of water current be y km/hr.

speed of boat in downstream = (x + y) km/hr and that in upstream = (x - y) km/hr.

Now distance = speed x time

Time = distance/speed

Time taken by the boat to travel 16 km upstream = 16/(x-y) hours and it takes 24/(x+y) hours to travel 24 km downstream.

from first condition -

 \frac{16}{x - y }  +  \frac{24}{x + y} = 6

FROM SECOND CONDITION:-

 \frac{36}{x - y }  +  \frac{48}{x + y }  = 13

by \: replacing \frac{1}{x - y} by \: m \: and \: \:  \\  \frac{1}{ x + y} by \: n \: we \: get

16m+24n=6

36m+48n=13

Solving equations (III) and (IV) m = 1/4, n = 1/12

Repalcing m, n by their original values we get

x - y = 4 . . .

x + y = 12 . . .

Solving equations (V), (VI) we get x = 8, y = 4

speed of the boat in still water is 8 km/hr. and speed of water current is 4 km/hr.

Answered by sharmav08826
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