Question

Ans this message one too please

Answer 1

divide 282 into two parts such that the eighth part of the first and the fifth part of the second are in the ratio 4:3

here is your answer ....

If first part is considered as x,
then second part is 282-x
eighth part of first =x/8
fifth part of second = (282-x)/5
given condition
x/8:(282-x)/5 = 4:3 x/8:(282-x)/5= 4/3 5x/8(282-x)= 4/3 15x = 32(282-x)
15x = 9024 - 32x 15x + 32x = 9024 47x = 9024 x = 9024/47 = 192
so,
first part = 192
second part = 282 - x = 282 - 192 = 90



hope it helps to you

Answer 2

ANSWER IS HERE

[tex] <b > <u > [\tex]
Two parts a & b
a + b = 282
"the eighth part of the first and the fifth part of the second are in the ratio 4:3."
Using the decimal equiv, 1/8 = .125 and 1/5 = .200
 = 
cross multiply
4(.2b) = 3(.125a)
.8b =.375a
b = 
b = .46875a
then
a + .46875a = 282
1.46875a = 282
a = 
a = 192
find b
b = 282-192
b = 90
:
The two parts are 192 and 90.
.125(192) = 24
.200(90) = 18
24/18 = 4/3

HOPE IT HELPS YOU

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