Question

Ans this onewords fast​

Answer 1

Answer:

16. Option(D)

17. Option(A)

Step-by-step explanation:

16.

Let u = sin x

On differentiating, we get

(du/dx) = cosx

Also,

Let v = cosx

On differentiating,we get

(dv/dx) = - sinx

Now,

(du/dx) = du/dx * dx/dv

            = du/dv

            = -cosx/sinx

            = -cotx

(17)

Given,

f(x) = x + 1

∴ fof(x) = f[f(x)]

= f(x) + 1

= (x + 1) + 1

= x + 2

Now,

On differentiating, we get

d/dx(fof)(x) = d/dx(x + 2)

=> d/dx(x) + d/dx(2)

[∴ d/dx(xⁿ) = nxⁿ⁻¹]

=> d/dx(x¹) + d/dx(x⁰)

=> 1 + 0

=> 1

Hope it helps!