Question

ans this please frnds​

Answer 1

1.)divide both atom with their atomic weight.

2.si=weight/28.8

weight=5. 76g

now, 5.76/28.8

=0.2

3.)cl=21.3/35.5 =0.6g

si:cl =0.2:0.6=1:3

therefore The empirical formula will be SiCl3

Answer 2

nhi aata ja ......lol