Question

Ans This plz as soon as possible ​

Answer 1

let

$y = \sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{6............ \infty } } } } } \\ \\ y = \sqrt{6 + y} \\ \\ sobs \\ \\ {y}^{2} = 6 + y \\ \\ {y}^{2} - y - 6 = 0 \\ \\ {y}^{2} + 2y - 3y - 6 = 0 \\ \\ y(y + 2) - 3(y + 2) = 0 \\ \\ (y + 2)(y - 3) = 0 \\ \\ y = - 2 \: not \: possible < 0 \\ \\ therefore \\ \\ y = 3 \\ \\ \sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{6............ \infty } } } } } = 3$

hope it helps

Answer 2

Answer:

Step-by-step explanation:

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