Question

ans this qst friends​

Answer 1

Answer:

not yhe ans

Explanation:

sry.For points

Answer 2

Question 1;

See,

• u (initial velocity of stone) = 10 m/s
• v ( final velocity of stone ) = 0 m/s
• a ( acceleration ) = 10 m/s²

We need to find the s ( distance/height attained by the stone )

Now, using 3rd equation of motion:

• v² - u² = 2as
• (0)² - (10)² = 2 × 10 × s
• - 100 = 20 × s
• - 100 / 20 = s
• -5 m = s

5 m is the height attained by the stone as distance can never be negative.

Now, we need to find t; use 1st or 2nd equation of motion, am using 1st equation of motion:

• v = u + at
• 0 = 10 + 10t
• -10 / 10 = t
• - 1 sec = t

Therefore, the time taken will be 1 second.

Do the rest by youself, they aren't that hard, just memorize the formulas and practice using them through these questions, it will help you.

Thanks! $\;$