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tanA = 1/√3 so A = 30 °
C = 90 °
B = 180 -(90+30) = 60 °
sinA = sin30 = 1/2
sinB = sin60 = √3/2
____________________ans
C = 90 °
B = 180 -(90+30) = 60 °
sinA = sin30 = 1/2
sinB = sin60 = √3/2
____________________ans
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