Question

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Answer 1

Step-by-step explanation:

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Answer 2

Question :- What Is The p th term of the AP whose m th term is n and n th term is m

Solution;-

$as \: per \: given$

$= > a_{m} = n \\ = > a + (m - 1)d = n ........(1)\\ \\ and \\ \\ = > a_{n} = m \\ = > a + (n - 1)d = m........(2) \\ \\ so \: by \: (2) - (1) \\ = > (n - {\cancel{1}} - m + {\cancel{1}})d = m - n \\ = > (n - m) d= m - n \\ = > - (m - n)d = m - n \\ = > d = - \frac{\cancel{m - n}}{\cancel{m - n}} \\ = > d = - 1 \\ \\ put \: the \: value \: of \: d = - 1 \: in \: (2) \\ = > a + (n - 1)( - 1) = m \\ = > a - n + 1 = m \\ = > a = m + n - 1 \\ \\ so \: p \: th \: term \: is \\ = > a_{p} \\ = > a + (p - 1)d \\ = > (m + n - 1) + (p - 1)( - 1) \\ = > m + n - 1 - p + 1 \\ = > m + n - p$

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