Math, asked by Ruchadeshmukh1, 8 months ago

Ans this question if u know the right answer✌✌✌​

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Answers

Answered by omsamarth4315
10

Answer:

important points :-

  • (a)^m × (a)^n = (a)^m + n .

  • (a)^m ÷ (a)^n = (a)^m + n .

  • (-) (-) = (+)

  • (-) (+) = (-)

  • (+) (+) = (+)

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follow the steps :-

  • 1) multiply the power of a² , with 3n + 2 in numerator.

  • 2) multiply the power of a⁴ , with 2n + 3 .

  • 3) taking the a common, simplify and will get the correct answer.

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Answer :-

= a^7 + 2n . (a)^ 2 × (3n + 2) / (a)^ 4×(2n + 3) .

= a^7+2n . (a)^6n + 4 / (a)^8n + 12

= (a)^ (7+2n) - (6n+4) / (a)^8n + 12

= 7 + 2n - 6n - 4 / 8n + 12

= 3 - 4n / 8n + 12 ans.

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Answered by Anonymous
1

Answer:

 \frac{ {a}^{7 + 2n}. ({a}^{2} ) {}^{3n + 2}  }{ ({a}^{4} ) {}^{3n + 3} }  =  \\  \\  =  >  \frac{ {a}^{7}. {a}^{2n}  .( {a}^{2} ) {}^{3n}. ({a}^{2}) {}^{2}   }{ ({a}^{4}) {}^{3n} .  ({a}^{4}  ){}^{3} }  \\  \\  \\  \\  \\  =  >  \frac{ {a}^{7} . {a}^{2n} . {a}^{6n}  {a}^{4} }{ {a}^{12n} . {a}^{12} }  \\  \\  \\  \\  =  >  \frac{ {a}^{11} . {a}^{8n} }{ {a}^{12n}. {a}^{12}  }  \\  \\  \\  \\  =  >  \frac{1}{ {a}^{12n - 8n}. {a}^{12 - 11}  }  \\  \\  \\  =  >  \frac{1}{ {a}^{4n}. {a}^{1}  }  =  >  \frac{1}{ {a}^{4n + 1} }  \:  \: ans....

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