Question

ans this question of Chemistry​

Answer 1

Answer:

I didn't Anderstand the question

Explanation:

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Answer 2

Answer:

1) Atomic mass of Na = 23 U

therefore 1 mole of Na = 23 grams = 6.023 × 10 ^ atoms (^=23)

46 grams of Na = 46/23 Moles = 2 moles

1 mole = 6.023 ×10^ (^=23)atoms

2 moles = 6.023×10^ × 2 (^=23)

= 12.0546×10^(^=23)atoms

Therefore 46 grams of Na contains 12.046×10^ atoms (^=23)

Explanation:

2) Molecular mass of O2 = 16 + 16 = 32 U (0+0)

Therefore 1 Mole of O2 =32 grams

8 grams = 8/32 moles

=0.25 moles

= 0.25 × 0.023 × 10^ (^=23) atoms

= 1.50 × 10^ (^=23) atoms ( Approx. )

Therefore 8 grams of O2 contain 1.50× 10 ^ (^=23)

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