Question

Ans this question please
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Answer 1

(i) The colour of the precipitate formed and the name of the compound is as follows:

The chemical reaction takes place between lead (II) nitrate and potassium iodide, so potassium nitrate and lead iodide form.

Nitrates are soluble in water, so the product potassium nitrate will be soluble. The lead halides are insoluble in water, so lead iodide will be precipitated.

(ii) The balanced chemical equation for this reaction is as follows:

The chemical formula of lead (II) nitrate is Pb(NO3)2 and potassium iodide KI.

Pb(NO3)2(aq)+KI(aq)→PbI2(s)+KNO3(aq)

On the left side of the equation, two nitrate ions are present, so add two on the left side, in front of potassium nitrate.

Pb(NO3)2(aq)+KI(aq)→PbI2(s)+2KNO3(aq)

Now on the left side, two iodide ions are present, so add two on the right side, in front of potassium iodide.

Pb(NO3)2(aq)+2KI(aq)→PbI2(s)+KNO3(aq)

So, the balanced chemical equation is, Pb(NO3)2(aq)+2KI(aq)→PbI2(s)+KNO3(aq)

(iii) We will determine the type of reaction as follows:

In a double displacement reaction, two compounds exchange their parts to form two new compounds. The reaction takes place between lead (II) nitrate and potassium iodide, the lead and potassium exchange their anions to give lead iodide and potassium nitrate.

So, this is a double displacement reaction