Question

ans this question pls

Answer 1

hay!!
its ur answer
$\frac{1}{x + 1} + \frac{2}{x + 2} = \frac{4}{x + 4} \\ \frac{x + 2 + 2x + 1}{ {x}^{2 } + 2} = \frac{4}{x + 4} \\ \frac{3x + 3}{ {x {}^{2} + 2}{} } = \frac{4}{x + 4} \\ \\ {3x }^{2} + 3x + 12x + 12 = {4x}^{2} + 8 \\ {3x}^{2} + 15x + 12 = {4x}^{2} - {3x}^{2} \\ 15x + 4 = {x}^{2} \\ {x}^{2} + 15x + 4$