Question

ans this question with method i will mark you as brainlist​

Answer 1

it is a very big question

Answer 2

Answer:

x^2-1

Step-by-step explanation:

since p(1)=0

(x-1) is a factor of p(x)

let the other factor be x+y , where y is a constant

now,

p(x)=(x-1)(x+y)

case i

p(0)=(0-1)(0+y) i.e. -1=(-1)y

i.e. y=1

case ii

p(2)=(2-1)(2+y)

3=1(2+y) i.e. y=1

that implies the other root is x+1

hence p(x) is (x-1)(x+1) i.e. x^2-1